4c^2=17c+15

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Solution for 4c^2=17c+15 equation:


Simplifying
4c2 = 17c + 15

Reorder the terms:
4c2 = 15 + 17c

Solving
4c2 = 15 + 17c

Solving for variable 'c'.

Reorder the terms:
-15 + -17c + 4c2 = 15 + 17c + -15 + -17c

Reorder the terms:
-15 + -17c + 4c2 = 15 + -15 + 17c + -17c

Combine like terms: 15 + -15 = 0
-15 + -17c + 4c2 = 0 + 17c + -17c
-15 + -17c + 4c2 = 17c + -17c

Combine like terms: 17c + -17c = 0
-15 + -17c + 4c2 = 0

Factor a trinomial.
(-3 + -4c)(5 + -1c) = 0

Subproblem 1

Set the factor '(-3 + -4c)' equal to zero and attempt to solve: Simplifying -3 + -4c = 0 Solving -3 + -4c = 0 Move all terms containing c to the left, all other terms to the right. Add '3' to each side of the equation. -3 + 3 + -4c = 0 + 3 Combine like terms: -3 + 3 = 0 0 + -4c = 0 + 3 -4c = 0 + 3 Combine like terms: 0 + 3 = 3 -4c = 3 Divide each side by '-4'. c = -0.75 Simplifying c = -0.75

Subproblem 2

Set the factor '(5 + -1c)' equal to zero and attempt to solve: Simplifying 5 + -1c = 0 Solving 5 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1c = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1c = 0 + -5 -1c = 0 + -5 Combine like terms: 0 + -5 = -5 -1c = -5 Divide each side by '-1'. c = 5 Simplifying c = 5

Solution

c = {-0.75, 5}

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